Variant 1 - Suppose we have 10 coins with Heads f…
AmITh - May 2, 2014
Variant 1 -
Suppose we have 10 coins with Heads faced up and 10 more with Tails.
Now we randomly divide the total(20) coins into two pipes of 10 coins each.
pipe1 pipe2
1 0
1 0
1 0
1 0
0 1
0 1
0 1
0 1
0 1
0 1
since there are 10 heads(1) and 10 tails(0) , if there are 4 Heads in pipe1, then remaining 6 should be in pipe2.
Now to get the Solution, flip all the coins in either of the pipes.
Result will be the identical number of Heads and Tails faced coins in both pipes.
Thanks for the solution Amith. :)